Problem 2: Decide if a Courtenay landing is safe
Solution in English:
- Calculate leaveTime plus tripLength. Store it in a variable called ‘earliestLandingTime’
- Find out what ‘windSpeed’ is happening at ‘earliestLandingTime’
- Is ‘windSpeeed’ less than or greater than 12knots?
- If ‘windSpeed’ is less than 12knots Mary can land at Courtenay
- If ‘windSpeed’ is equal to or greater than 12knots Mary must contact the Marshall
Problem 3: Find an alternate landing time/location
Solution in English:
- Calculate the ‘newLandingTime’ by adding the time delayed to the previous ‘earliestLandingTime’
- Find out the new available landing times. Store it in a variable called ‘newAvailableTimes’
- Compare newLandingTime to each newAvailableTime
- If newAvailableTime is earlier than newLandingTime, move to the next newAvailableTime
- If newAvailableTime is equal to or later than newLandingTime, book this time
- If there are no newLandingTime’s available – Mary must land at Smits
Problem 4: Book a dinner reservation
- Determine if Mary & Loiuse are landing at Smits or at Courtenay
- If they are landing at Smits add 45 minutes to the newLandingTime to determine the reservationTime
- Then Loiuse must contact the Marshall for the loaner car
- If they are landing at Courtenay, they must add 20 minutes to the newLandingTime to determine the reservationTime
- Then Loiuse must call a taxi
